100 Exercises To Learn Rust - 4.6 String slice 풀기

// TODO: Ticket의 접근자를 &Str을 사용해 다시 구현하세요.

pub struct Ticket {
    title: String,
    description: String,
    status: String,
}

impl Ticket {
    pub fn new(title: String, description: String, status: String) -> Ticket {
        if title.is_empty() {
            panic!("Title cannot be empty");
        }
        if title.len() > 50 {
            panic!("Title cannot be longer than 50 bytes");
        }
        if description.is_empty() {
            panic!("Description cannot be empty");
        }
        if description.len() > 500 {
            panic!("Description cannot be longer than 500 bytes");
        }
        if status != "To-Do" && status != "In Progress" && status != "Done" {
            panic!("Only `To-Do`, `In Progress`, and `Done` statuses are allowed");
        }

        Ticket {
            title,
            description,
            status,
        }
    }

    pub fn title(&self) -> &String {
        &self.title
    }

    pub fn description(&self) -> &String {
        &self.description
    }

    pub fn status(&self) -> &String {
        &self.status
    }
}

 

 

풀이

pub fn title(&self) -> &str {
        &self.title
    }

    pub fn description(&self) -> &str {
        &self.description
    }

    pub fn status(&self) -> &str {
        &self.status
    }

 

 

접근자의 반환 타입을 &str로 바꾸기만 하면 된다.